An ice block with a piece of lead embedded in it floats in water. If the ice melts the water level
(1) Rises
(2) Falls
(3) Remains same
(4) Falls first and then rises
Answer: (2) If ╧Б1 is the density of the lead piece of volume v, the volume of water displaced by the ice block and the lead piece while floating is V╧Й = (V–v) ╧Б1 + v ╧Б1. When the ice melts, the lead piece sinks in water since ╧Б1 is greater than the density of water. The water produced by the melted ice has the volume (V-v) ╧Б1 and the volume displaced by the lead piece is v. So, the total volume of the water produced by ice and that displaced by the lead piece is V ╧Й1 = (V–v) ╧Б1+ v ╧Б1< V ╧Й. So, the water level goes down.
